MCQs Preparation

Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ?

A. 3 days
B. 4 days
C. 6 days
D. 8 days

C. 6 days

12 children take 16 days to complete a work.

so,

1 child’s 1 day’s work=1/(12*16)

1 child’s 1 day’s work=1/192

8 adults take 12 days to complete a work.

So, 

1 adult’s day’s work=1/(8*12)

1 adults day’s work=1/96

But, after working of 3 days, 16 adults left

so, 

16 adults 3 day’s work= 16*3*1/96

16 adults 3 day’s work=1/2

therefore,

the remaining work will be:

Remaining work=1-1/2

Remaining work=1/2

Now (6 adults+ 4 Children) 1 day’s work will be:

(6 adults+4 children) 1 day’s work=6/96+4/192

(6 adults+4 children) 1 day’s work= 16/192

(6 adults+4 children) 1 day’s work=1/12

so,

1/12th of the work is done by them in 1 day

thus,

they take following days to complete the remaining work.

(1÷1/12)*1/2

(1*12)*1/2

12/2

6 days

 

Submitted by: Admin

Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ? Read More »

A trader owes a merchant Rs. 10,028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest 12% per annum, how much cash should he pay?

A. Rs. 9025.20
B. Rs. 9200
C. Rs. 9600
D. Rs. 9560

B. Rs. 9200

Required money =P.W. of Rs.10028 due 9 months hence
= Rs (10028*100)/(100+(12*9/12))
= Rs.9200

A trader owes a merchant Rs. 10,028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest 12% per annum, how much cash should he pay? Read More »

A shopkeeper earns a profit of 10% after allowing a discount of 20% on the marked price. The cost price of the article whose marked price is Rs. 880, is =_______ ?

A. Rs. 704
B. Rs. 640
C. Rs. 774
D. Rs. 680

B. Rs. 640

Market price of the article = Rs.880

After discount selling price of the article

= (880*80)/100

= Rs. 704

Cost Price of the article

= (704*100)/110

= Rs. 640 (Answer)

A shopkeeper earns a profit of 10% after allowing a discount of 20% on the marked price. The cost price of the article whose marked price is Rs. 880, is =_______ ? Read More »

In the following question, two equations are given. On their basis you have to determine the relation between x and y and then give answer I. 3x^2 – 7x + 2 = 0 II. 2y^2 – 11y + 15 = 0

A. x < y
B. x > y
C. x ≤ y
D. x ≥ y

A. x < y

Equation I
3x² – 7x + 2 = 0
3x²-6x-x+2=0
3x (x-2)-1(x-2)=0
(3x -1)(x – 2) = 0

3x -1 = 0
3x =1
x = 1/3 , x-2=0
x = 2

Equation II
2y² -11y +15 = 0
2y² – 6y – 5y +15 = 0
2y (y-3)-5(y-3)=0
(2y- 5)(y-3)= 0
(2y-5)=0
y = 5/2
Also (y – 3) = 0
y=3

Now comparing x and y

x = 1/3 is smaller than 5/2 and 3
x= 2 is smaller than 3 and 5/2

Thus we see that x is smaller than y

x<y

In the following question, two equations are given. On their basis you have to determine the relation between x and y and then give answer I. 3x^2 – 7x + 2 = 0 II. 2y^2 – 11y + 15 = 0 Read More »

In the following question, there are two equations. Solve them and give answer I. 20P^2 + 31P + 12 = 0 II. 21Q^2 + 23Q + 6 = 0

A. P > Q
B. P < Q
C. P ≤ Q
D. P ≥ Q

B. P < Q

I. 20P²+31P+ 12 = 0

On doing factorization

20P²+15P+16P+12 = 0
5P (4P + 3) + 4 (4P + 3) = 0
(4P + 3) (5P + 4) = 0
P = -3/4, -4/5 P — 0.75, -0.80

II. 21Q² + 23Q + 6 = 0

On doing factorization

21Q² + 9Q + 14Q + 6 = 0
3Q (7Q + 3) + 2 (7Q + 3) = 0
(7Q + 3)(3Q + 2) = 0
Q = -3/7, -2/3 Q = – 0.43, -0.66

On taking Q = – 0.43

P < Q (for both the values of P) equation I

On taking Q = -0.66

P < Q (for both the values of P) equation II

From equation I and II
P < Q

In the following question, there are two equations. Solve them and give answer I. 20P^2 + 31P + 12 = 0 II. 21Q^2 + 23Q + 6 = 0 Read More »

In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer. I. x^2 + 3x + 2 = 0 II. 2y^2 = 5y

A. x < y
B. x > y
C. x ≤ y
D. x = y

A. x < y

We will separately solve both equations

Equation 1:
x²+3x+2=0
x²+2x+x+2=0
x (x + 2)+1 (x +2)= 0
(x + 2) * (x + 1)= 0
x=-2 , x=-1

Equation 2:
2y² = 5y
2y² – 5y = 0
2y * (y – 5/2) = 0
y=0 , y= 5/2

Both values of y are positive while both values of x are negative
x<y

In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer. I. x^2 + 3x + 2 = 0 II. 2y^2 = 5y Read More »

A candidate, appearing for an examination, was asked to find 3/14 of a certain number but mistakenly, he found 3/4 of it. When he cross checked his answer, he found his answer was 150 more than the correct answer. Which number was given in the examination for this calculation?

A. 160
B. 180
C. 240
D. 280

D. 280

Let the required number be x
So, as per the question, we have
3x/4 – 3x/14 = 150
(21x-6x)/28 = 150
x = (150*28)/15
x = 280

Thus, the given number is 280

A candidate, appearing for an examination, was asked to find 3/14 of a certain number but mistakenly, he found 3/4 of it. When he cross checked his answer, he found his answer was 150 more than the correct answer. Which number was given in the examination for this calculation? Read More »

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