Maths MCQs

Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ?

A. 3 days
B. 4 days
C. 6 days
D. 8 days

C. 6 days

12 children take 16 days to complete a work.

so,

1 child’s 1 day’s work=1/(12*16)

1 child’s 1 day’s work=1/192

8 adults take 12 days to complete a work.

So, 

1 adult’s day’s work=1/(8*12)

1 adults day’s work=1/96

But, after working of 3 days, 16 adults left

so, 

16 adults 3 day’s work= 16*3*1/96

16 adults 3 day’s work=1/2

therefore,

the remaining work will be:

Remaining work=1-1/2

Remaining work=1/2

Now (6 adults+ 4 Children) 1 day’s work will be:

(6 adults+4 children) 1 day’s work=6/96+4/192

(6 adults+4 children) 1 day’s work= 16/192

(6 adults+4 children) 1 day’s work=1/12

so,

1/12th of the work is done by them in 1 day

thus,

they take following days to complete the remaining work.

(1÷1/12)*1/2

(1*12)*1/2

12/2

6 days

 

Submitted by: Admin

Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ? Read More »

A trader owes a merchant Rs. 10,028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest 12% per annum, how much cash should he pay?

A. Rs. 9025.20
B. Rs. 9200
C. Rs. 9600
D. Rs. 9560

B. Rs. 9200

Required money =P.W. of Rs.10028 due 9 months hence
= Rs (10028*100)/(100+(12*9/12))
= Rs.9200

A trader owes a merchant Rs. 10,028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest 12% per annum, how much cash should he pay? Read More »

A shopkeeper earns a profit of 10% after allowing a discount of 20% on the marked price. The cost price of the article whose marked price is Rs. 880, is =_______ ?

A. Rs. 704
B. Rs. 640
C. Rs. 774
D. Rs. 680

B. Rs. 640

Market price of the article = Rs.880

After discount selling price of the article

= (880*80)/100

= Rs. 704

Cost Price of the article

= (704*100)/110

= Rs. 640 (Answer)

A shopkeeper earns a profit of 10% after allowing a discount of 20% on the marked price. The cost price of the article whose marked price is Rs. 880, is =_______ ? Read More »

In the following question, two equations are given. On their basis you have to determine the relation between x and y and then give answer I. 3x^2 – 7x + 2 = 0 II. 2y^2 – 11y + 15 = 0

A. x < y
B. x > y
C. x ≤ y
D. x ≥ y

A. x < y

Equation I
3x² – 7x + 2 = 0
3x²-6x-x+2=0
3x (x-2)-1(x-2)=0
(3x -1)(x – 2) = 0

3x -1 = 0
3x =1
x = 1/3 , x-2=0
x = 2

Equation II
2y² -11y +15 = 0
2y² – 6y – 5y +15 = 0
2y (y-3)-5(y-3)=0
(2y- 5)(y-3)= 0
(2y-5)=0
y = 5/2
Also (y – 3) = 0
y=3

Now comparing x and y

x = 1/3 is smaller than 5/2 and 3
x= 2 is smaller than 3 and 5/2

Thus we see that x is smaller than y

x<y

In the following question, two equations are given. On their basis you have to determine the relation between x and y and then give answer I. 3x^2 – 7x + 2 = 0 II. 2y^2 – 11y + 15 = 0 Read More »

In the following question, there are two equations. Solve them and give answer I. 20P^2 + 31P + 12 = 0 II. 21Q^2 + 23Q + 6 = 0

A. P > Q
B. P < Q
C. P ≤ Q
D. P ≥ Q

B. P < Q

I. 20P²+31P+ 12 = 0

On doing factorization

20P²+15P+16P+12 = 0
5P (4P + 3) + 4 (4P + 3) = 0
(4P + 3) (5P + 4) = 0
P = -3/4, -4/5 P — 0.75, -0.80

II. 21Q² + 23Q + 6 = 0

On doing factorization

21Q² + 9Q + 14Q + 6 = 0
3Q (7Q + 3) + 2 (7Q + 3) = 0
(7Q + 3)(3Q + 2) = 0
Q = -3/7, -2/3 Q = – 0.43, -0.66

On taking Q = – 0.43

P < Q (for both the values of P) equation I

On taking Q = -0.66

P < Q (for both the values of P) equation II

From equation I and II
P < Q

In the following question, there are two equations. Solve them and give answer I. 20P^2 + 31P + 12 = 0 II. 21Q^2 + 23Q + 6 = 0 Read More »

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