Sound waves are _________ waves.
A. Transverse
B. Electromagnetic
C. Longitudinal
D. None of these
C. Longitudinal
Sound waves are _________ waves. Read More »
Mocks
Deficiency of Vitamin-D results in __________?
A. night blindness
B. rickets
C. scurvy
D. hair fall
B. rickets
Deficiency of Vitamin-D results in __________? Read More »
A man buys an article for 10% less than its value and sells it for 10% more than its value. His gain or loss percent is:________?
A. no profit, no loss
B. 20% profit
C. less than 20% profit
D. more than 20% profit
D. more than 20% profit
Let the article be of worth rupees x.
then, as per the statement, the cost price at 10% less value will be:
C.P=[(100-10)/100]*x
C.P=90x/100
C.P=9x/10 rupees
Sells at 10% more value means:
S.P= x*[(100+10)/100]
S.P=110x/100
S.P=11x/10 rupees
As 11x/10 > 9x/10, this means, man has gain percentage.
So,
Gain=S.P-C.P
Gain=11x/10-9x/10
Gain=(11x-9x)/10
Gain=2x/10
Gain=x/5 rupees
But, we need gain%.
So,
Gain%=(Gain/C.P)*100
Gain%=[(x/5)/(9×10)]* 100
Gain%=(x/5÷9x/10)*100
Gain%=[(x/5)*(10/9x)]*100
Gain%=(2x/9x)*100
Gain%=(2/9)*100
Gain%=200/9
or
Gain%=22*(2/9)
So, Profit is more than 20%
If 5% more is gained by selling an article for Rs. 350 than by selling it for Rs. 340, the cost of the article is:________?
A. Rs. 50
B. Rs. 160
C. Rs. 200
D. Rs. 225
C. Rs. 200
Let Cost price of the article be Rs.x
When Selling price is Rs.340 then,
Gain% = (340-x)/x * 100
When Selling price is Rs. 350 then,
Gain% = (350-x)/x * 100
Hence,
Additional % gain= (350-x)/x * 100 – (340-x)/x * 100
Additional % gain= 5=[350−x−340+x] * 100/x [It is given that gain% = 5%]
5x=1000
x=Rs.200
Cost price of article is Rs.200
The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs. 3. The ratio of the two selling prices is:__________?
A. 51:52
B. 52:53
C. 51:53
D. 52:55
B. 52:53
Let cost price (CP) of the article be X rupees.
For 4% profit, SP=CP+4% of CP = 1.04X
For 6% profit, SP=CP+6% of CP = 1.06X
It is given that cash differences between selling price is Rs 3
1.06X−1.04X=3
0.02X=3
X=150
so,
Selling price of first article = 1.04X
Selling price of first article = 1.04×150
Selling price of first article = 156 Rupees
and,
Selling price of second article = 1.06X
Selling price of second article = 1.06×150
Selling price of second article = 159 Rupees
Ratio of selling prices = 156/159
Ratio of selling prices = 52:53
The length of a rectangular increased by 10% and it’s breadth is decreased by 10 %. Then the area of the new rectangle is_________?
A. Neither increased nor decreased
B. Increased by 1%
C. Decreased by 1%
D. Decreased by 10%
C. Decreased by 1%
A=l*b
before change
A=100%lb
let l’ be the length after increment
so,
l’=l+l*10/100
l’=l*110/100
l’=l*11/10
let b’ be the breadth after decrement
so,
b’=b-b*10/100
b’=b*90/100
b’=b*9/10
so, new area will be
A’=l’*b’
A’=(l*11/10)*(b*9/10)
A’=l*b*99/100
Change in Percentage will be
A’-A
99lb/100 – 100lb/100
-1/100
or
-1% here negative show sign show % is decreasing by 1
The marked price of a watch was Rs. 720. A man bought the same for Rs. 550.80, after getting two successive discounts, the first 10%. What was the second discount rate ?
A. 12%
B. 14%
C. 15%
D. 18%
C. 15%
Market price of a watch = Rs. 720
After 1st discount = 90% of 720
After 1st discount = 90/100×720
After 1st discount = Rs. 648
Cost price of watch = Rs. 550.80
Difference = 648 – 550.80
Difference = Rs. 97.20
2nd discount = (97.20/648)×100
2nd discount = 9720/648
2nd discount = 15%