Selected MCQs

The sum of three numbers is 98. If the ratio of the first to the second is 2 : 3 and that of the second to the third is 5 : 8, then the second number is?

A. 20
B. 30
C. 48
D. 58

B. 30

Let the three numbers be A,B and C respectively
A:B = 2:3 ———— i
B:C = 5:8 ———— ii

Multiplying (i) by 5 and (ii) by 3,

A:B = 10:15
B:C = 15:24

A:B:C=10:15:24

Sum of ratio = 10+15+24=49
B = (15/49)*90
​B = 30

The sum of three numbers is 98. If the ratio of the first to the second is 2 : 3 and that of the second to the third is 5 : 8, then the second number is? Read More »

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

A. 39, 30
B. 41, 32
C. 42, 33
D. 43, 34

C. 42, 33

Let one of the students secure x marks.

then, the other student secures (x+9) marks.

the sum of both their marks is equal to

56% of the sum of both means

56% of x+x+9 (x+9 obtained 56% marks when we both students marks)

or

(56/100)* x+x+9

so,

x+9=56% of (x+x+9)

x+9=(56/100)*(2x+9)

x+9=(112x+504)/100

100(x+9)=112x+504

100x+900=112x+504

900-504=112x-100x

396=12x

396/12=x

33=x

or

x=33

so the mark of other student will be

x+9

33+9

42

Marks obtained by both students are 33 and 42.

Submitted by: Admin

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are: Read More »

40% of a number is more than 20% of 650 by 190. Find the number?

A. 600
B. 700
C. 800
D. 900

C. 800

Let the number be x.

40% of a number means: (40/100) * x

20% of 650 means: (20/100)*650

by means = 190

So,

(40/100)*x is more than (20/100) * 650 means (40/100)*x is higher than (20/100)*650

Therefore, 

(40/100)*x-(20/100)*650=190

40x/100-(20*650)/100=190

2x/5-130=190

2x/5=190+130

2x/5=320

2x=320*5

2x=1600

x=1600/2

x=800 (Answer)

Submitted by: Admin

40% of a number is more than 20% of 650 by 190. Find the number? Read More »

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:________?

A. 4.37%
B. 5%
C. 6%
D. 8.75%

B. 5%

Percentage increase in population in 10 years
= [(262500-175000)/175000 ]​ x 100
= 50%
Thus, average increase in population per year = 5% (Answer)

Submitted by: Admin

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:________? Read More »

In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?

A. 6.25
B. 6.5
C. 6.75
D. 7

A. 6.25

For first 10 overs, run rate = 3.2
⇒ Runs scored = 3.2×10=32
Total runs to be scored = 282
Runs Left to be scored in 40 overs= (282-32)/40
= 250/40
Required Run-Rate in remaining overs = 6.25 (Answer)

Submitted by: Admin

In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs? Read More »

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