Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
A. 39, 30
B. 41, 32
C. 42, 33
D. 43, 34
C. 42, 33
Let one of the students secure x marks.
then, the other student secures (x+9) marks.
the sum of both their marks is equal to
56% of the sum of both means
56% of x+x+9 (x+9 obtained 56% marks when we both students marks)
or
(56/100)* x+x+9
so,
x+9=56% of (x+x+9)
x+9=(56/100)*(2x+9)
x+9=(112x+504)/100
100(x+9)=112x+504
100x+900=112x+504
900-504=112x-100x
396=12x
396/12=x
33=x
or
x=33
so the mark of other student will be
x+9
33+9
42
Marks obtained by both students are 33 and 42.
Submitted by: Admin