Two numbers are in the ratio 5:4 and their difference is 10.What is the largest number? A. 40B. 50C. 60D. 30 Answer B. 50 Solution Let the the two numbers be 5x and 4x, thenthe difference of the two numbers will be:5x-4x=10x=10now, let’s find the numbers5x5*10=504x4*10=40so, the largest number is 50. Submitted by: Admin Two numbers are in the ratio 5:4 and their difference is 10.What is the largest number? Read More »
What is the ratio of Faheem’s salary to Imran’s salary to Naveed’s salary if Faheem makes 80,000 rupees ,Imran 70,000 rupees and Naveed makes 50,000 rupees ? A. 80:70:60B. 8:7:5C. 4:7:5D. 7:8:5 Answer B. 8:7:5 Solution Faheem : Imran : Naveed  80000 : 70000 : 50000divide all by 10000     8 : 7 : 5 Submitted by: Admin What is the ratio of Faheem’s salary to Imran’s salary to Naveed’s salary if Faheem makes 80,000 rupees ,Imran 70,000 rupees and Naveed makes 50,000 rupees ? Read More »
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are: A. 39, 30B. 41, 32C. 42, 33D. 43, 34 Answer C. 42, 33 Solution Let one of the students secure x marks.then, the other student secures (x+9) marks.the sum of both their marks is equal to56% of the sum of both means56% of x+x+9 (x+9 obtained 56% marks when we both students marks)or(56/100)* x+x+9so,x+9=56% of (x+x+9)x+9=(56/100)*(2x+9)x+9=(112x+504)/100100(x+9)=112x+504100x+900=112x+504900-504=112x-100x396=12x396/12=x33=xorx=33so the mark of other student will bex+933+942Marks obtained by both students are 33 and 42. Submitted by: Admin Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are: Read More »
40% of a number is more than 20% of 650 by 190. Find the number? A. 600B. 700C. 800D. 900 Answer C. 800 Solution Let the number be x.40% of a number means: (40/100) * x20% of 650 means: (20/100)*650by means = 190So,(40/100)*x is more than (20/100) * 650 means (40/100)*x is higher than (20/100)*650Therefore, (40/100)*x-(20/100)*650=19040x/100-(20*650)/100=1902x/5-130=1902x/5=190+1302x/5=3202x=320*52x=1600x=1600/2x=800 (Answer) Submitted by: Admin 40% of a number is more than 20% of 650 by 190. Find the number? Read More »
A man spends Rs. 3,300/-. This was 75% of his monthly income. His monthly income is ____. A. 4,000B. 4,400C. 4,500D. 3,500 Answer B. 4,400 Solution Man spends 3300 rupees which is equal to 75% of his monthly income. This entails that man used 3/4 of income of his income and 25% of his income is remaining.So, divide 3300/3=1100multiply 1100 x 4 = 4400 (Answer) Submitted by: Admin A man spends Rs. 3,300/-. This was 75% of his monthly income. His monthly income is ____. Read More »
Ghafoor went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items? A. Rs. 15B. Rs. 15.70C. Rs. 19.70D. Rs. 20 Answer C. Rs. 19.70 Solution Let the amount of taxable purchases be  Rupees: xGiven, 6% of x=30 paisa=100/30​ Rupees⇒ x=(30/100​×100/6​)=5⇒ Cost of tax free items: [25−(5+0.30)]Rs.19.70 (Answer) Submitted by: Admin Ghafoor went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items? Read More »
Ramees buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods. A. Rs. 6876.10B. Rs. 6999.20C. Rs. 6654D. Rs. 7000 Answer A. Rs. 6876.10 Solution Rebate=6%MP=Rs.6650SP=94%×6650SP=(94/100) x 6650SP=6251 rupeesSince, Sales tax=10%Total amount Ramees will have to pay:-=10% × 6251 + 6251=Rs.(625.1+6251)= Rs.6876.10 (Answer) Submitted by: Admin Ramees buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods. Read More »
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:________? A. 4.37%B. 5%C. 6%D. 8.75% Answer B. 5% Solution Percentage increase in population in 10 years= [(262500-175000)/175000 ]​ x 100 = 50%Thus, average increase in population per year = 5% (Answer) Submitted by: Admin The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:________? Read More »
The average of two numbers is XY.If one number is equal to X ,the other number is equal to_________? A. XB. 2YC. XY-XD. 2 XY -X Answer D. 2 XY -X Solution x and y are two numbers.(x+y)/2=xy (average of two numbers)If one number is equal to x, thenother number will be,(x+y)/2=xyx+y=2xyy=2xy+x (Answer) Submitted by: Admin The average of two numbers is XY.If one number is equal to X ,the other number is equal to_________? Read More »
The temperature at noon in LHR ,Pakistan was 6 deg on Monday ,4deg on Tuesday,2deg below zero on Wednesday,3deg below zero on Thursday, 0 deg on Friday ,3 deg on Saturday ,and 6 deg on Sunday. What was the average temperature at noon for the week ? A. 14 degB. -2 degC. 2 degD. 7 deg Answer C. 2 deg Solution The temperature on Monday= 6The temperature on Tuesday= 4The temperature on Wednesday= -2The temperature on Thursday= -3The temperature on Friday= 0The temperature on Saturday= 3The temperature on Sunday= 6 Number of Days=7So, the average temperature for the week will be:=(6+4+(-2)+(-3)+0+3+6)/7=2 degree Submitted by: Admin The temperature at noon in LHR ,Pakistan was 6 deg on Monday ,4deg on Tuesday,2deg below zero on Wednesday,3deg below zero on Thursday, 0 deg on Friday ,3 deg on Saturday ,and 6 deg on Sunday. What was the average temperature at noon for the week ? Read More »