In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer. I. x^2 + 3x + 2 = 0 II. 2y^2 = 5y

A. x < y
B. x > y
C. x ≤ y
D. x = y

Answer

A. x < y

Solution

We will separately solve both equations

Equation 1:
x²+3x+2=0
x²+2x+x+2=0
x (x + 2)+1 (x +2)= 0
(x + 2) * (x + 1)= 0
x=-2 , x=-1

Equation 2:
2y² = 5y
2y² – 5y = 0
2y * (y – 5/2) = 0
y=0 , y= 5/2

Both values of y are positive while both values of x are negative
x<y

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