Complusory Subjects

Q: 8(a) CSS GSA 2023 Solved – Ali buys an oven for Rs.36800 and sells it at a gain of 8.5%. For how much does he sell it?

Formulas To be Used In Order To Solve This Problem

Gain % = (Gain X 100)/(C.P)

Gain = S.P – C.P

Given:

C.P = Rs. 36800

Gain% = 8.5%

To Find:

S.P = ?

Solution:

Gain % = (Gain X 100)/(C.P)

8.5 = (Gain X 100)/(36800 )

(8.5 X 36800)/100 = Gain

Gain = 3128

So,

 Gain=S.P-C.P

or

Gain + C.P = S.P

3128+36800= S.P

S.P = 39928

Ali Sold The Oven For Rs. 39928 at a gain of 8.5%.

Q: 8(a) CSS GSA 2023 Solved – Ali buys an oven for Rs.36800 and sells it at a gain of 8.5%. For how much does he sell it? Read More »

Q:8(b) CSS GSA 2023 Solved – A card is drawn at random from a box containing 12 cards numbered 1,2,3,4,5,…,12. Find the probability of drawing.

(i) ‘8’

(ii) an even number

(iii) a perfect square

(iv) a negative number

(v) a number less than 13

Since, Sample Space or

S=1,2,3,4,5,6,7,8,9,10,11,12

Then,

(i) ‘8’

Solution:

S=1,2,3,4,5,6,7,8,9,10,11,12

Let A be the event selecting ‘8’, then n(A)=8

P(A)=(n(A))/(n(S))

P(A)=1/12 

As 8 numbered card is only one in the box, so the Probability of drawing a

card ‘8’ from box will be 1/12 

(ii) an even number

Solution:

S=1,2,3,4,5,6,7,8,9,10,11,12

Let A be the event selecting ‘even number’, then n(A)=2,4,6,8,10,12

P(A)=(n(A))/(n(S))

P(A)=6/12 

P(A)=1/2 

As Even number cards is six in the box, so the Probability of drawing a card an even number from box will be 1/2 

(iii) a perfect square

Solution:

S=1,2,3,4,5,6,7,8,9,10,11,12

Let A be the event selecting ‘a perfect square’, then n(A)=1, 4, 9

P(A)=(n(A))/(n(S))

P(A)=3/12 

P(A)=1/4  

As a perfect square number cards is 3 in the box, so the Probability of drawing a card a

perfect square from box will be 1/4  

(iv) a negative number

Solution:

S=1,2,3,4,5,6,7,8,9,10,11,12

Let A be the event selecting ‘a negative number’, then n(A)=0

P(A)=(n(A))/(n(S))

P(A)=0/12 

P(A)=0

As there is no any negative number card in the box, so the Probability of drawing a card a negative number from box will be 0

(v) a number less than 13

Solution:

S=1,2,3,4,5,6,7,8,9,10,11,12

Let A be the event selecting ‘a number less than 13’, then n(A)=1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12

P(A)=(n(A))/(n(S))

P(A)= 12/12 

P(A)= 1

As all numbers in the box are less than 13, so the Probability of drawing a card a

Number less than 13 from box will be 1.

Q:8(b) CSS GSA 2023 Solved – A card is drawn at random from a box containing 12 cards numbered 1,2,3,4,5,…,12. Find the probability of drawing. Read More »

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